[gmx-users] mdrun error
Hector Mrz-Seara Monne
hseara at netscape.net
Sat Oct 2 20:11:45 CEST 2004
spoel at xray.bmc.uu.se wrote:
>On Sat, 2004-10-02 at 16:48, Hector Mrz-Seara Monne wrote:
>
>
>>>>
>>>>
>>>>
>>>OK that looks fine. Have you verified (md.log file) that these settings
>>>have been incorporated in the tpr file?
>>>
>>>
>>It seems that every thing is ok
>>
>>
>>>Have you tried visualising the trajectory?
>>>
>>>
>>Every thing seems normal if you make a overall view. But after
>>checking one by one all the monomers one of them seem to kill
>>itself.The main part of the sistem is very rigid with many impropials
>>defined along it, benzene-N=N-benzene ( it must be all in a plane). I
>>notice when I was trying to parametrice the molecule that if I try to
>>keep it complete plane whit impropial then the structure crash in a
>>dyanmic, It seems like the molecule enter in a kind of resonance
>>effect that finish with unnatural bond legth and angles and the
>>crashing of the system. I pass through this problem changing some
>>impropials for propials with a loose in the planarity. It seems that
>>this fenomenom is crashing my system again. Have you any suggestion?
>>Thank you.
>>
>>
>
>Try equilibrating at lower temperature and/or with a shorter time step.
>In particular since you describe this resonance thing. Could it be that
>your force constants are too high? You should have roughly 20 time steps
>in a complete period of the fastest motion.
>
>
>
>
Thanks in advance for all your help, it's been quite useful for me in
order to increase my knowledge on this suite.
I've been thinking in the last suggestion and I'm not sure about the
meaning. As I understand if I use high constants
for defining my proper dihedrals I have to reduce my time steep that
actually is quite small 1fs only or work at lower temperature.
Here the *.itp file of the monomer contain this lines that I have
specifically modify to have a planarity system.
.....
[ dihedrals ]
;ai aj ak al fu c0 c1 m c0 c1 m
9 12 10 8 2 0.0 1673.6 0 0.0 1673.6 0 ; IDI CBA CAD
CAE CAU
14 15 13 11 2 0.0 1673.6 0 0.0 1673.6 0 ; IDI CBB NAV
CAF CAG
17 16 20 18 2 0.0 1673.6 0 0.0 1673.6 0 ; IDI CBC NAW
CAH CAI
22 23 21 19 2 0.0 1673.6 0 0.0 1673.6 0 ; IDI CBD OAY
CAJ CAK
27 26 29 28 2 0.0 1673.6 0 0.0 1673.6 0 ; IDI CAZ CAT
OAX OAC
17 18 19 22 2 0.0 1673.6 0 0.0 1673.6 0 ; IDI CBC CAI
CAK CBD
18 19 22 21 2 0.0 1673.6 0 0.0 1673.6 0 ; IDI CAI CAK
CBD CAJ
19 22 21 20 2 0.0 1673.6 0 0.0 1673.6 0 ; IDI CAK CBD
CAJ CAH
22 21 20 17 2 0.0 1673.6 0 0.0 1673.6 0 ; IDI CBD CAJ
CAH CBC
21 20 17 18 2 0.0 1673.6 0 0.0 1673.6 0 ; IDI CAJ CAH
CBC CAI
20 17 18 19 2 0.0 1673.6 0 0.0 1673.6 0 ; IDI CAH CBC
CAI CAK
9 10 11 14 2 0.0 1673.6 0 0.0 1673.6 0 ; IDI CBA CAE
CAG CBB
10 11 14 13 2 0.0 1673.6 0 0.0 1673.6 0 ; IDI CAE CAG
CBB CAF
11 14 13 12 2 0.0 1673.6 0 0.0 1673.6 0 ; IDI CAG CBB
CAF CAD
14 13 12 9 2 0.0 1673.6 0 0.0 1673.6 0 ; IDI CBB CAF
CAD CBA
14 15 17 16 2 0.0 1673.6 0 0.0 1673.6 0 ; IDI CBB NAV
CBC NAW
13 12 9 10 2 0.0 1673.6 0 0.0 1673.6 0 ; IDI CAF CAD
CBA CAE
12 9 10 11 2 0.0 1673.6 0 0.0 1673.6 0 ; IDI CAD CBA
CAE CAG
4 3 2 1 1 0.0 5.9 3 0.0 5.9 3 ; DI
CAN CAM CAL CAA
.....
11 14 15 16 1 180.0 53.5 2 180.0 33.5 2 ; DI CAG CBB
NAV NAW *
15 16 17 20 1 180.0 53.5 2 180.0 33.5 2 ; DI NAV NAW
CBC CAH *
.....
25 26 27 29 1 0.0 0.4 6 0.0 0.4 6 ; DI CAR
CAT CAZ OAX
26 27 29 30 1 180.0 16.7 2 180.0 16.7 2 ; DI CAT CAZ
OAX HE2 *
Do you know if your advise works equally for both proper and improper
dihedrals? If not can you tell me the diference?
I think for your coment that the dihedral with the asterisk that are the
problematic? witch time step will you use, or do you know any
way to avoid the restriction that my system contain?
Thank you very much for taking your time to answer me, David. If you
think you need any other information or that is not clear what
I'm asking for just tell me and I can send you any indormation or foles
that you thing could be usefull to solve my actual problems
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