[gmx-users] free energy: annihilation
dmobley at gmail.com
Sat Aug 26 15:04:47 CEST 2006
> I'm trying to annihilate a complete DMSO box at constant volume. The
> dG/dlam values converge nicely but when I integrate the curve I get a
> Helmholtz energy that is almost exactly a factor of two different from
> the experimental value.
Maybe this is too basic, but are you doing the transformation in
vacuum also and subtracting? I assume you are trying to compute
something like a hydration free energy, which means you have to
complete a thermodynamic cycle that takes you from the full molecule
in water to the full molecule in vacuum. I don't know any way to do
this in GROMACS currently without also doing a separate vacuum
calculation, because of the intramolecular interactions.
> Am I forgetting something here? Should I treat the intramolecular
> degrees of freedom in a special manner?
You can, but you don't have to. One thing that can sometimes help
convergence is to only turn off the intermolecular LJ interactions,
which you can do by modifying the pairs list and explicitly stating
appropriate LJ parameters, or (presumably) by using the new pairs
types that Berk implemented, although I still haven't tested these
>Currently I am only turning off
> the LJ and Coulomb terms. Should I turn off the angles and dihedrals as
No, you don't want to do that.
The other thing that can make some difference is your protocol. In particular:
(1) Are you turning off the LJ and Coulomb terms simultaneously? I've
always found that it is a lot harder to converge this calculation and
get reliable answers than if you do the Coulomb interactions first and
then do the LJ interactions.
(2) What soft core parameters are you using for the LJ interactions?
Some work much better than others. (My free energy tutorial has some
information about doing the LJ transformation. If you want to do
something really basic, you could try reproducing my value for
I also list the soft core parameters that are "optimal" there.)
(3) Make sure your PME parameters are good enough; sometimes free
energy calculations can be pretty sensitive to this sort of thing
(4) How curved is your dV/dlambda plot? TI can end up making a
nontrivial amount of integration error, especially if you have nearly
equal positive and negative areas under the curve (in which case the
integration error could be on the same order of magnitude as the total
> David van der Spoel, PhD, Assoc. Prof., Molecular Biophysics group,
> Dept. of Cell and Molecular Biology, Uppsala University.
> Husargatan 3, Box 596, 75124 Uppsala, Sweden
> phone: 46 18 471 4205 fax: 46 18 511 755
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