[gmx-users] Re: Re: how to calculate the vaporation enthalpy of pure small organic compound (David van der Spoel)
David van der Spoel
spoel at xray.bmc.uu.se
Sun Oct 25 13:15:58 CET 2009
Jinyao Wang wrote:
> Hi David,
> Thank you for your help. I am very sorry to trouble you.
> I have know your means that the gas-phase energy should be considered.
> But I am confused that you said "the gas-phase energy (with com removed) and add kT".
> What is "the gas-phase energy (with com removed) " and Could you talk about the details?
Better look it up in a textbook, e.g.Allen & TIldesley. The equations
are also in my paper
J. Phys. Chem. B. 105 pp. 2618-2626 (2001).
>>> Jinyao Wang wrote:
>>>> Hi gmx-users,
>>>> I want to calcualted the the vaporation enthalpy of benzaldehyde I
>>>> think that the the vaporation enthalpy is the sum of non-bond
>>>> interacion among the benzaldehyde molecule. So I made a NPT system
>>>> simulation including 512 benzaldehyde molecule. The following is the
>>>> intermolecule nonbond interaction using the g_energy.
>>>> LJ-(SR)= -21128.7 Kj/mol
>>>> LJ-(LR)= -889.855 Kj/mol
>>>> Coulomb-(SR)= -3884.6 Kj/mol
>>>> Coul.-recip = -2261.51 Kj/mol
>>>> the sum of non-bond interaction = LJ-(SR) + LJ-(LR) + Coulomb-(SR) +
>>>> Coul.-recip = 28164.665 Kj/mol
>>>> But the experimental value of he vaporation enthalpy = 50.3 Kj/mol
>>>> I have no ideal that why they have so much different. Now I don't know
>>>> how to solve it.
>>>> Any suggestion will be appreciated.
>>> These are totals for the intermolecular energy of the system. I'm
>>> guessing you didn't use "-nmol 512" to calculate these results?
>> And then subtract the gas-phase energy (with com removed) and add kT.
> Jinyao Wang
> wangjy at ciac.jl.cn
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David van der Spoel, Ph.D., Professor of Biology
Molec. Biophys. group, Dept. of Cell & Molec. Biol., Uppsala University.
Box 596, 75124 Uppsala, Sweden. Phone: +46184714205. Fax: +4618511755.
spoel at xray.bmc.uu.se spoel at gromacs.org http://folding.bmc.uu.se
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