[gmx-users] neutralizing membrane protein in lipid bilayer +water
Justin A. Lemkul
jalemkul at vt.edu
Tue Sep 29 19:15:16 CEST 2009
ram bio wrote:
> Dear Justin,
>
> I was trying to model a part of the protein involved in the active
> site and these terminal residues i think have no role in active site
> as per the literature, so i was removing the residues whose
> coordinates were not properly assigned (missing H atoms) so the
> initial terminus changed to serine, we can even find such problems in
> crystal structures where the coordinates don't get resolved
Crystal structures never have H, but we simulate them all the time. Their
geometry is largely predictable :)
Consider whether or not these deletions will have an effect. While not
catalytically active, do they have any role in maintaining the protein's
structure? Just my $0.02. Don't chop out what doesn't seem to work; it might
(or might not) be important.
-Justin
> properly...I think as the number of residues changed the total charge
> also changed, these are some of the limitations that i think occur to
> exactly predict the structure and activity for some proteins.
>
> Thanks
>
> Ram
>
> On Tue, Sep 29, 2009 at 10:16 PM, Justin A. Lemkul <jalemkul at vt.edu> wrote:
>>
>> ram bio wrote:
>>> Dear Justin,
>>>
>>> Thanks and as per suggestion, now i have corrected the original
>>> modelled pdb file and executed the pdb2gmx command with n-terminus
>>> option 1 (NH2) and C-terminus option 1 (COOH), now the net charge is
>>> 11.00, and the toplogy file has the first and last residues as under:
>>>
>>>
>>> 1 NL 1 SER N 1 -0.66 14.0067
>>> ; qtot -0.66
>>> 2 H 1 SER H1 1 0.44 1.008
>>> ; qtot -0.22
>>> 3 H 1 SER H2 1 0.44 1.008
>>> ; qtot 0.22
>>> 4 CH1 1 SER CA 1 -0.22 13.019 ;
>>> qtot 0
>>> 5 CH2 1 SER CB 2 0.266 14.027
>>> ; qtot 0.266
>>> 6 OA 1 SER OG 2 -0.674 15.9994
>>> ; qtot -0.408
>>> 7 H 1 SER HG 2 0.408 1.008 ;
>>> qtot 0
>>> 8 C 1 SER C 3 0.45 12.011
>>> ; qtot 0.45
>>> 9 O 1 SER O 3 -0.45 15.9994 ;
>>> qtot 0
>>>
>>> 2950 N 285 PRO N 1280 0 14.0067 ;
>>> qtot 11
>>> 2951 CH1 285 PRO CA 1281 0 13.019 ;
>>> qtot 11
>>> 2952 CH2R 285 PRO CB 1281 0 14.027 ;
>>> qtot 11
>>> 2953 CH2R 285 PRO CG 1282 0 14.027 ;
>>> qtot 11
>>> 2954 CH2R 285 PRO CD 1282 0 14.027 ;
>>> qtot 11
>>> 2955 C 285 PRO C 1283 0.33 12.011
>>> ; qtot 11.33
>>> 2956 O 285 PRO OT 1283 -0.45 15.9994
>>> ; qtot 10.88
>>> 2957 OA 285 PRO O 1283 -0.288 15.9994
>>> ; qtot 10.59
>>> 2958 H 285 PRO HO 1283 0.408 1.008 ;
>>> qtot 11
>>>
>>> Please suggest if it is ok, so that i can continue with the further steps.
>>>
>> No, that's your job as a scientist :) Besides, I can't necessarily say. Do
>> those protonation states model reality? Is your model a reasonable
>> representation of a true physical system? Does the net charge make sense?
>> Your original first residue was threonine, now it's serine. What exactly
>> was your "fix" to this problem?
>>
>> These are the things that you should always consider. Only once you've
>> solved these issues can you proceed with any degree of confidence.
>>
>> -Justin
>>
>>> Thanks,
>>>
>>> Ram
>> --
>> ========================================
>>
>> Justin A. Lemkul
>> Ph.D. Candidate
>> ICTAS Doctoral Scholar
>> Department of Biochemistry
>> Virginia Tech
>> Blacksburg, VA
>> jalemkul[at]vt.edu | (540) 231-9080
>> http://www.bevanlab.biochem.vt.edu/Pages/Personal/justin
>>
>> ========================================
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>
--
========================================
Justin A. Lemkul
Ph.D. Candidate
ICTAS Doctoral Scholar
Department of Biochemistry
Virginia Tech
Blacksburg, VA
jalemkul[at]vt.edu | (540) 231-9080
http://www.bevanlab.biochem.vt.edu/Pages/Personal/justin
========================================
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