[gmx-users] restarting from cpt and binary identical
Peter C. Lai
pcl at uab.edu
Thu Apr 21 00:00:26 CEST 2011
I have a fairly stupid question about restart from a checkpoint and binary
identical messages, probably because I can't understand the doco.
When I restart (or extend) a double-precision run from a checkpoint involving
either dlb or even a different decomposition count (say I changed the number of
parallel threads), I get a message that says it restarted but the
trajectory is not binary identical.
My question is: I assume this trajectory will continue from the last set of
double-precision coordinates and velocities in the cpt file? What is the
loss in precision/error propagation of the resulting trajectory as compared
to if I started the entire run from the begining? (say I am extending my
trajectory from 1ns to 10ns). I guess I understand that both trajectories
would be "equally valid" but not binary identical, but what does this mean
in terms of things like ultimate RMSD measurements and so forth? I don't
necessarily care that the two concatenated trajectory files will not cmp to
zero.
--
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Peter C. Lai | University of Alabama-Birmingham
Programmer/Analyst | BEC 257
Genetics, Div. of Research | 1150 10th Avenue South
pcl at uab.edu | Birmingham AL 35294-4461
(205) 690-0808 |
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