[gmx-users] Dihedral Restraints

Alexander Bujotzek bujotzek at zib.de
Mon Mar 7 10:37:56 CET 2011


The piece of code in dihres.c does it right (at least for the energy I
would say... can't say anything about the force)... but the equation in
the manual is wrong or at least misleading.

>
>
> On 05/03/11, Sai Pooja  <saipooja at gmail.com> wrote:
>> Hi,
>>
>>  
>>
>> In Manual 4.5.3, the potential for dihedral restraints is the following:
>>
>>  
>>
>> Phi* = (Phi - Phi0)MOD 2Pi
>>
>>  
>>
>> Where Phi is the instantaneous dihedral and Phi0 is the reference
>> dihedral. And the MOD2Pi, I assume, ensures a difference <2Pi.
>>
>>  
>>
>> The Potential is: V=0.5*K*(Phi* - Phi0 -deltaPhi)**2          for all
>> Phi*  > deltaPhi and so on ...
>>
>>  
>>
>> I am just confused if this is just a typo? Why are we subtracting Phi0
>> TWICE??
>>
>>
>
> There's an outstanding Redmine issue on this topic -
> http://redmine.gromacs.org/issues/597. Please contribute anything useful.
>
> Mark
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