[gmx-users] Shift functions
Mark Abraham
Mark.Abraham at anu.edu.au
Fri Feb 10 15:41:20 CET 2012
On 11/02/2012 1:19 AM, Elisabeth wrote:
>
>> Hello all,
>>
>> Does the shift function use group based truncation?
>
> See the discussion of charge groups in manual section 3.4.2.
>
>
> Thanks Mark.
>
> -1- First of all if I am right charge groups in gromacs language in
> identical to "group based truncations"?
Using charge groups as the indivisible entity upon which neighbour list
construction is based is using "group based truncations". The usual
alternative is using atoms as the, well, *atomic* unit. The former can
be equivalent to the latter if there's one atom per charge group.
>
>
> Manual 342: "This reduces the cut-off effects from the charge-charge
> level to the dipole-dipole level, which decay much faster"
>
> 2- I am not able to realize why we go from charge-charge the
> dipole-dipole changes?
Charge groups are constructed to have neutral charge (or integer charge
where necessary). To first order, the difference between any such group
being in the neighbour list of another such group or not (according to
the cut-off radius) is equivalent to a point dipole being in the cut-off
sphere or not. Charge groups with arbitrary charge (or partially-charged
atoms, when using atom-based truncation) do not have this quality, and
the distance at which a charge-charge interaction is significant is much
larger than that of a dipole-dipole.
>
>
>
>> In the manual I see: by using shifted forces there is no need for
>> charge groups (=group based?!) in the neighbor list?
>>
>> Can anyone shed some light on calculation of shifted forces?
>
> What's not clear from the above and 4.1.5?
>
>
> 3- I understand that use of shift makes the potentials have continuous
> derivatives at cutoffs but that how this makes use of charge groups
> unnecessary, I dont see!
Remember that the neighbour list is constructed to permit the
computation of a finite number of interactions with the central
atom/group. You want to stop computing them when they're close enough to
zero that you don't care. If they actually go to zero, then you don't
care. If they decay as 1/r (charge-charge) then at typical r_c values
you should care. If they decay as 1/r^2 (dipole-dipole, IIRC) then at
typical r_c values things are OK.
If the value of the force is non-zero at the cut-off, then there is an
interaction at that distance and not one just past that distance. This
generates artefacts that are serious for non-zero charges at the kinds
of cut-off distances for which force fields are parametrized, but much
less serious if computed over neutral charge groups.
If the value of the force is zero at the cut-off (i.e. shift potential),
then no atom or charge group has any interaction with the central
group/atom at that distance, so you don't need to care about whether the
truncation is based on atoms or groups. You do have to care about the
effect of the modified Coulomb potential, however.
>
> 4- and based on 3, shift forces dont neglect tail corrections for LJ
> as cutoffs do? Am I correct?
There's a cut-off used with shifted forces (indeed, in GROMACS it
*defines* the shift), so I don't understand your question.
Mark
>
> Thank you
>
>
>
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