[gmx-users] Re: Thermodynamic Integration Glu -> Ala Mutation
Sai Kumar Ramadugu
sramadugu at gmail.com
Thu Jun 7 19:08:44 CEST 2012
Any suggestions on this topic?
Thanks again for your time.
Dear Gromacs Users,
> I am trying to find out the relative free energy difference of binding of
> a ligand with wild type protein (Glutamate residue) and mutant protein
> (Alanine residue).
>
> For charge part of the mutation, this is what I'm planning to do:
>
> ; residue 40 GLU rtp GLU q -1.0
> 552 opls_238 40 GLU N 191 -0.5 14.0067
> opls_238 -0.5 14.0067 ; qtot 0.5
> 553 opls_241 40 GLU H 191 0.3 1.008
> opls_241 0.3 1.008 ; qtot 0.8
> 554 opls_224B 40 GLU CA 191 0.14 12.011
> opls_224B 0.14 12.011 ; qtot 0.94
> 555 opls_140 40 GLU HA 191 0.06 1.008
> opls_140 0.06 1.008 ; qtot 1
> 556 opls_136 40 GLU CB 192 -0.12 12.011
> opls_135 -0.18 12.011 ; qtot 0.88
> 557 opls_140 40 GLU HB1 192 0.06 1.008
> opls_140 0.06 1.008 ; qtot 0.94
> 558 opls_140 40 GLU HB2 192 0.06 1.008
> opls_140 0.06 1.008 ; qtot 1
> 559 opls_274 40 GLU CG 193 -0.22 12.011
> opls_140 0.06 1.008 ; qtot 0.78
> 560 opls_140 40 GLU HG1 193 0.06 1.008
> DUM_140 0.0 1.008 ; qtot 0.84
> 561 opls_140 40 GLU HG2 193 0.06 1.008
> DUM_140 0.0 1.008 ; qtot 0.9
> 562 opls_271 40 GLU CD 194 0.7 12.011
> DUM_271 0.0 12.011 ; qtot 1.6
> 563 opls_272 40 GLU OE1 194 -0.8 15.9994
> DUM_272 0.0 15.9994 ; qtot 0.8
> 564 opls_272 40 GLU OE2 194 -0.8 15.9994
> DUM_272 0.0 15.9994 ; qtot 0
> 565 opls_235 40 GLU C 195 0.5 12.011
> opls_235 0.5 12.011 ; qtot 0.5
> 566 opls_236 40 GLU O 195 -0.5 15.9994
> opls_236 -0.5 15.9994 ; qtot 0
>
>
> I added the DUM_140, DUM_271,DUM_272 atomtypes in ffnonbonded.itp.
> Further I added the bondtypes, angletypes and dihedraltypes in
> ffbonded.itp for state B.
>
> In order to maintain the electroneutrality, I am mutating a K+ ion to
> dummy as well. For the K+ going to dummy, I added a DUM_408 atomtype as
> well.
>
> *The questions I have are as follows:*
> *During the charge mutation will my dummy atoms have sigma and epsilon as
> 0.0? Since Ala residue does not have Cgamma, Cdelta and the oxygen as well
> as the Hgamma, all the dummy atoms should have sigma and epsilon as zero.
> Am I correct for this assumption?*
> *Further as I am mutating one ion, I dont want the mutating ion to come
> close to other ions (I have three K+ ions as my protein has -3 charge) as
> well as the protein atoms. Hence I'm having position restraints on the
> three ions. *
> *For the ion that is mutating to dummy, should I have have position
> restraints on dummy atom as well for the B state topology?*
>
> The section of topology for the K+ going to dummy is as follows:
>
> [ moleculetype ]
> ; Name nrexcl
> KM 1
>
> [ atoms ]
> ; nr type resnr residue atom cgnr charge mass typeB
> chargeB massB
> 1 opls-408 1 KM KM 1 1 39.0983
> DUM_408 0.0 39.0983
>
> #ifdef POSRES_ION
> ; Position restraint for each Potassium ion
> [ position_restraints ]
> ; i funct fcx fcy fcz
> 1 1 1000 1000 1000 0 0 0
> #endif
>
> Here I defined the KM as K+ that will go to dummy and other two K+ ions
> are represented as regular K+ ions.
> I'm pasting the regular K+ ion part of the topology below.
>
> [ moleculetype ]
> ; Name nrexcl
> K 1
>
> [ atoms ]
> ; nr type resnr residue atom cgnr charge mass typeB
> chargeB massB
> 1 opls_408 1 K K 1 1 39.0983
>
> #ifdef POSRES_ION
> ; Position restraint for each Potassium ion
> [ position_restraints ]
> ; i funct fcx fcy fcz
> 1 1 1000 1000 1000
> #endif
>
> Let me know if you need more information.
>
> Thanks for your time,
>
> Regards
> Sai
>
>
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