[gmx-users] g_analyze
afsaneh maleki
maleki.afsaneh at gmail.com
Tue Sep 17 12:16:39 CEST 2013
Dear all
When I use the following command:
g_analyze -f free_bi_0.9.xvg -av average_0.9
I got
set average standard deviation *std. dev. /
sqrt(n-1) *…
SS1 6.053822e+01 3.062230e+01 1.936724e-02 …
What is “*std. dev. / sqrt(n-1)” *?
I know that
Standard deviation (SD) for samples is quall to sqrt[{sum((x-xmean)*2)/n-1}]
Standard error* *(SE) = Standard deviation/sqrt( n)
n is number of samples.
But I don’t know what is the concept of the “*std. dev. / sqrt(n-1)”*? is
it SE?
Sincerely
Afsaneh
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