[gmx-users] g_analyze

afsaneh maleki maleki.afsaneh at gmail.com
Tue Sep 17 12:16:39 CEST 2013

Dear all

When I use the following command:

g_analyze   -f    free_bi_0.9.xvg  -av  average_0.9

I got

set       average              standard  deviation       *std. dev.  /
sqrt(n-1)    *…

SS1    6.053822e+01     3.062230e+01              1.936724e-02        …

What is “*std. dev.  / sqrt(n-1)” *?

I know that

Standard deviation (SD) for samples is quall to sqrt[{sum((x-xmean)*2)/n-1}]

Standard error* *(SE) = Standard deviation/sqrt( n)

n is number of samples.

But I don’t know what is the concept of the “*std. dev.  / sqrt(n-1)”*?  is
it SE?



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