[gmx-users] question of perturbing order in single topology FEP, gromacs
asaffarhi at post.tau.ac.il
asaffarhi at post.tau.ac.il
Wed Nov 29 19:22:39 CET 2017
Dear Peng,
You can transform each of the molecules seperately.
You can remove the nonbonded interactions of the atoms that are
different between the compared molecules.
Then, if you have only one dihedral relating the different atoms to
the common atoms in each molecule it does not need to be removed.
Also, the bond angle and covalent bond terms do not need to be
removed. This is based on NVT but may be also accurate for NPT.
We also saw that the order of transforming matters but maybe you can
try without removing the bonded terms.
For more details you can read:
http://www.sciencedirect.com/science/article/pii/S0010465516303411
Best,
Asaf
Quoting Peng He <hepeng.yanglu at gmail.com>:
> HI, all,
>
> I am recently doing some test FEP calculations to get familiar, I am
> preparing a system of ethane -> methanol using Amber gaff force field and
> single topology method.
>
> " 4 [ atomtypes ]
> 5 ;name bond_type mass charge ptype sigma epsilon
> Amb
> 6 c3 c3 0.00000 0.00000 A 3.39967e-01
> 4.57730e-01 ; 1.91 0.1094
> 7 hc hc 0.00000 0.00000 A 2.64953e-01
> 6.56888e-02 ; 1.49 0.0157
> 8 oh oh 0.00000 0.00000 A 3.06647e-01
> 8.80314e-01 ; 1.72 0.2104
> 9 h1 h1 0.00000 0.00000 A 2.47135e-01
> 6.56888e-02 ; 1.39 0.0157
> 10 dh hc 0.00000 0.00000 A 0.00000 0.00000
> 11 ho ho 0.00000 0.00000 A 0.00000e+00 0.00000e+00
> 12 [ moleculetype ]
> 13 ;name nrexcl
> 14 UNK 3
> 15
> 16 [ atoms ]
> 17 ; nr type resi res atom cgnr charge mass ; qtot
> bond_type
> 18 1 c3 1 UNK C1 1 -0.095100 12.01000 c3
> 0.116700 12.01000
> 19 2 c3 1 UNK C2 2 -0.095100 12.01000 oh
> -0.598801 12.01000
> 20 3 hc 1 UNK H1 3 0.031700 1.00800 h1
> 0.028700 1.00800
> 21 4 hc 1 UNK H2 4 0.031700 1.00800 h1
> 0.028700 1.00800
> 22 5 hc 1 UNK H3 5 0.031700 1.00800 h1
> 0.028700 1.00800
> 23 6 hc 1 UNK H4 6 0.031700 1.00800 ho
> 0.396000 1.00800
> 24 7 hc 1 UNK H5 7 0.031700 1.00800 dh
> 0.000000 1.00800
> 25 8 hc 1 UNK H6 8 0.031700 1.00800 dh
> 0.000000 1.00800
> 26
> 27 [ bonds ]
> 28 ; ai aj funct r k
> 29 1 2 1 1.5375e-01 2.5179e+05 1.4233e-01 2.6501e+05
> 30 1 3 1 1.0969e-01 2.7665e+05 1.0969e-01 2.7665e+05
> 31 1 4 1 1.0969e-01 2.7665e+05 1.0969e-01 2.7665e+05
> 32 1 5 1 1.0969e-01 2.7665e+05 1.0969e-01 2.7665e+05
> 33 2 6 1 1.0969e-01 2.7665e+05 9.7300e-02 3.1079e+05
> 34 2 7 1 1.0969e-01 2.7665e+05 1.0969e-01 2.7665e+05
> 35 2 8 1 1.0969e-01 2.7665e+05 1.0969e-01 2.7665e+05
> ...
> ..."
>
> I know to perturbing from large molecule(ethane) to small(methanol), I need
> to perturb the electrostatic interaction first than vdw, But I don't know
> where to perturb the bonded lambdas. I have tested different orders of
> Bonded lambdas, and I have got a quite different answer which seems odd to
> me. I have a table for that
> stage1 stage2 stage3 dG(kj) dG(kcal)
> single topology solv q/bonded/vdw -14.36 -3.43
> bonded q vdw -13.79 -3.30
> bonded/q vdw -14.91 -3.56
> q bonded vdw -17.13 -4.09
> q bonded/vdw -20.22 -4.83
> q vdw bonded -25.2 -6.02
> single topology vac q/bonded/vdw 10.32 2.47
> bonded q vdw 9.53 2.28
> bonded/q vdw 9.1 2.17
> q bonded vdw 8.71 2.08
> q bonded/vdw 9.64 2.30
> q vdw bonded 9.84 2.35
> The desolvation free energy of ethane is -2.48 and methanol 3.48kcal.
> The best result which close the cyclo for ethane,vac -> ethane, solv ->
> methanol, solv -> methanol,vac -> ethane,vac is perturbing all three
> together(q/bonded/vdw) followed by perturbing bonded/q together then vdw.
> The worst is to decouple bonded lambdas the last. When I try dual topology
> method, there is no such difference where to place the bonded lambdas...
>
> I am confused that which one should used and why others are not OK?
>
> Thank you
> Best
> Peng
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