[gmx-users] Protonated ligand free energy calculation in water
Rolly Ng
rollyng at gmail.com
Fri Apr 10 19:35:24 CEST 2020
Dear GROMACS users,
I read and followed Dr. Lemkul's tutorial on Free Energy Calculation on the
webpage, http://www.mdtutorials.com/gmx/free_energy/index.html
It is very helpful and easy to follow, but my ligand is protonated so the
atomic charges in the topol.top are non-zero.
The above tutorial also indicates that Coulombic interactions can be
applied, but I would like to know how it can be done?
vdw_lambdas = 0.00 0.05 0.10 ... 1.00 1.00 1.00 ... 1.00
coul_lambdas = 0.00 0.00 0.00 ... 0.00 0.05 0.10 ... 1.00
Here is the [ atoms ] in my topol.top and your advise is highly appreciated!
[ atoms ]
; nr type resnr residue atom cgnr charge mass typeB
chargeB massB
; residue 1 MT3 rtp MT3 q 2.0
1 nh 1 MT3 N1 1 -0.83505600 14.010000 ; qtot
-0.835056
2 cz 1 MT3 C1 2 0.85138300 12.010000 ; qtot
0.016327
3 nh 1 MT3 N2 3 -0.51848300 14.010000 ; qtot
-0.502156
4 nh 1 MT3 N3 4 -0.83505600 14.010000 ; qtot
-1.337212
5 c3 1 MT3 C2 5 -0.34660600 12.010000 ; qtot
-1.683818
6 nh 1 MT3 N4 6 0.02468700 14.010000 ; qtot
-1.659131
7 nh 1 MT3 N5 7 -0.80566500 14.010000 ; qtot
-2.464796
8 cz 1 MT3 C3 8 0.57808800 12.010000 ; qtot
-1.886708
9 c3 1 MT3 C4 9 -0.34660600 12.010000 ; qtot
-2.233314
10 hn 1 MT3 H1 10 0.47045200 1.008000 ; qtot
-1.762862
11 hn 1 MT3 H2 11 0.47045200 1.008000 ; qtot
-1.292410
12 hn 1 MT3 H3 12 0.38772400 1.008000 ; qtot
-0.904686
13 hn 1 MT3 H4 13 0.47045200 1.008000 ; qtot
-0.434234
14 h1 1 MT3 H5 14 0.17432200 1.008000 ; qtot
-0.259912
15 h1 1 MT3 H6 15 0.17432200 1.008000 ; qtot
-0.085590
16 h1 1 MT3 H7 16 0.17432200 1.008000 ; qtot
0.088732
17 hn 1 MT3 H8 17 0.45892600 1.008000 ; qtot
0.547658
18 h1 1 MT3 H9 18 0.17432200 1.008000 ; qtot
0.721980
19 h1 1 MT3 H10 19 0.17432200 1.008000 ; qtot
0.896302
20 h1 1 MT3 H11 20 0.17432200 1.008000 ; qtot
1.070624
21 hn 1 MT3 H12 21 0.45892600 1.008000 ; qtot
1.529550
22 hn 1 MT3 H13 22 0.47045200 1.008000 ; qtot
2.000002
Thank you,
Rolly
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