[gmx-users] OPLS definition of Phenyl palmitate
Ebert Maximilian
m.ebert at umontreal.ca
Sat Jun 6 00:12:31 CEST 2015
Hi,
a small little update. I saw that CT OS C_2 O_2 and CT OS C_2 CT are defined OPLS/AA. I used these parameters now to define CA OS C_2 O_2 and CA OS C_2 CT in OPLS/AA. Any thoughts on that? I really have difficulties to visualize dihedral angles and I am not sure if this would actually give roughly the same geometry or not.
Thanks and have a good weekend.
Max
> On Jun 5, 2015, at 4:38 PM, Ebert Maximilian <m.ebert at umontreal.ca> wrote:
>
> Dear list,
>
> I ran into some problem to define the topology of phenyl palmitate. My main problem is a missing dihedral angle definition in OPLS/AA. Here is a sketch of the molecule without hydrogen (I hope it turns out to be readable in the email):
>
>
> O17
> ||
> C21 - C20 C16 (C)n
> / \ / \ / \
> C22 C19 - O18 C15 C1
> \ /
> C23 - C24
>
> I think I defined the atom types correctly:
>
> [ atoms ]
> ; nr type resi res atom cgnr charge mass
> 1 opls_768 1 PNR C22 4 -0.1952 12.01100
> 2 opls_145 1 PNR C21 5 -0.0500 12.01100
> 3 opls_145 1 PNR C20 6 -0.1550 12.01100
> 4 opls_145 1 PNR C23 7 -0.0500 12.01100
> 5 opls_145 1 PNR C24 8 -0.1550 12.01100
> 6 opls_472 1 PNR C19 9 0.1591 12.01100
> 7 opls_473 1 PNR O18 10 -0.3732 15.99940
> 8 opls_465 1 PNR C16 11 0.6491 12.01100
> 9 opls_466 1 PNR O17 12 -0.5100 15.99940
> 10 opls_136 1 PNR C15 13 -0.1264 12.01100
> 11 opls_136 1 PNR C14 14 -0.0804 12.01100
> 12 ….
>
> The problem is now in the ester since there is no dihedral definition of CA OS C_2 O_2 and CA OS C_2 CT in OPLS/AA. I assigned C19 the atom type 472 which is Cipso phenyl ester with type CA and hence O18 473 (AA -OR phenyl ester). Do I understand 472 correctly? How can I resolve the missing two dihedral angles?
>
> I also wanted to know if somebody has an idea what is meant by: AA C: esters - for R on C=O, use #280-#282 of the atom type opls_465. Do I need in this case to assign opls_280 to C15 and opls_282 to the corresponding hydrogens since they are the R of the ester?
>
> Thank you very much for your advice,
>
> Max
>
>
>
>
>
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