[gmx-users] To trjcat or not to trjcat

[Alex]

Since the first frame of trajectory (N+1) will be the same as the last 
frame of trajectory N, then you need to do two things:

>
> 1. Use trjconv -b 50 to remove the first frame from all but the first 
> trajectory.  This eliminates the duplicate frames.
> 2. Then use trjconv -t0 to set a new start time for each trajectory.  
> This is easily done as part of a loop in a shell script.
> 3. trjcat
> 4. Profit?
>
> -Justin
>
This sounds like exactly what I wanted, thank you!