[gmx-users] To trjcat or not to trjcat
nedomacho at gmail.com
Thu Dec 15 16:13:52 CET 2016
Since the first frame of trajectory (N+1) will be the same as the last
frame of trajectory N, then you need to do two things:
> 1. Use trjconv -b 50 to remove the first frame from all but the first
> trajectory. This eliminates the duplicate frames.
> 2. Then use trjconv -t0 to set a new start time for each trajectory.
> This is easily done as part of a loop in a shell script.
> 3. trjcat
> 4. Profit?
This sounds like exactly what I wanted, thank you!
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