[gmx-users] Energy values for 1 step NVT/NVE simulation of 100 water molecules
Anh Vo
atv55 at msstate.edu
Wed Mar 18 06:28:23 CET 2020
Hi everyone,
I am doing just a small simulation of 100 water molecules (after energy
minimization, I run only 1 step of NVT and then get the Total energy,
Potential and Kinetic energy from .edr file). The Kinetic energy is around
1 kJ/mol, while the Potential and Total energy is below - 2000 kJ/mol
(around - 2405 kJ/mol). Similar results are obtained at 310K and 1K, as
well as when I run NVE instead of NVT. Is it possible for the energy to be
that much negative? If not, what could I have missed?
Please see my settings in .mdp file as below for the 1 step NVT (For NVE,
similar settings are used, but with tcoupl = no and pcoupl = no).
define = -DREST_ON -DSTEP6_1
integrator = md
dt = 0.0005
nsteps = 1
nstlog = 1
nstxout = 1
nstvout = 1
nstfout = 1
nstcalcenergy = 1
nstenergy = 1
;
cutoff-scheme = Verlet
nstlist = 10
rlist = 1.0
coulombtype = pme
rcoulomb = 1.0
vdwtype = Cut-off
vdw-modifier = Force-switch
rvdw_switch = 0.8
rvdw = 1.0
;
tcoupl = berendsen
tc_grps = SOL_ION
tau_t = 1.0
ref_t = 310
;
pcoupl = no
;
constraints = h-bonds
constraint_algorithm = LINCS
;
nstcomm = 100
comm_mode = linear
comm_grps = SOL_ION
;
refcoord_scaling = com
Thank you very much for your help. I really appreciate it.
Best,
Anh Vo
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